Question

f(x)= x+√x
Qual é a derivada da função f?

Answer 1

$f(x)=x+\sqrt{x}\\\\f(x)=x^1+x^{\frac{1}{2}}\\\\\\\frac{df(x)}{dx}=1\;x^{1-1}+\frac{1}{2}x^{\frac{1}{2}-1}\\\\\frac{df(x)}{dx}=1\;x^{0}+\frac{1}{2}x^{-\frac{1}{2}}\\\\\frac{df(x)}{dx}=1+\frac{1}{2\sqrt{x}}$