• Matéria: Matemática
  • Autor: lucaif
  • Perguntado 9 anos atrás

Alguem me ajuda com esse cálculo
 x^{2} - \sqrt{64} + \sqrt[3]{8} + \frac{10000000000000000}{5000000000000}+  }   \pi <br /><br />


lucaif: Considere pi = 3,15

Respostas

respondido por: 3478elc
2





x² - 8 + 2 + 2000+ 3,15

x² + 1997,15
respondido por: Verkylen
0
x^2-\sqrt{64}+\sqrt[3]{8}+\dfrac{10000000000000000}{5000000000000}+\pi=\\\\x^2-\sqrt{2\cdot2\cdot2\cdot2\cdot2\cdot2}+\sqrt[3]{2\cdot2\cdot2}+\dfrac{10000}{5}+3,15=\\\\x^2-\sqrt{2^2\cdot2^2\cdot2^2}+\sqrt[3]{2^3}+2000+3,15=\\\\x^2-\sqrt{8^2}+2+2000+3,15=\\\\x^2-8+2+2000+3,15=\\\\\boxed{x^2+1997,5}
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