• Matéria: Matemática
  • Autor: lucaif
  • Perguntado 9 anos atrás

Alguem me ajuda? Considere Pi igual a 3,1415926535897932384626433832

 \sqrt{1024} +  \pi

Respostas

respondido por: Verkylen
0
\sqrt{1024}+\pi=\\\\\sqrt{1024}+3,1415926535897932384626433832=\\\\\sqrt{2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2}+3,1415926535897932384626433832=\\\\\sqrt{2^2\cdot2^2\cdot2^2\cdot2^2\cdot2^2}+3,1415926535897932384626433832=\\\\\sqrt{32^2}+3,1415926535897932384626433832=\\\\32+3,1415926535897932384626433832=\\\\35,1415926535897932384626433832

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Verkylen: Kkk, obrigado. :)
respondido por: sbrosa
1
√1024 + π = 32 + 3,141592653589793234626433832 =
35,1415926535897932384626433832
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