Question

uma mola de constante elastica 40 n/m sofre uma deformaçao de 0,04 m.Calcule a energia potencial acumulada pela mola

Answer 1

Bom dia!


$Epe = \frac{k \times {x}^{2} }{2}$


k = constante elástica

x= deformação da mola


$Epe = \frac{40 \times {0.04}^{2} }{2}$


$Epe = \frac{40 \times 0.0016}{2}$

Epe=0,032j


abraços

Answer 2

$\Large{\begin{array}{l}\tt E_p=\dfrac{k\cdot x^2}{2}\\\\\tt E_p=\dfrac{40\cdot(0{,}04)^2}{2}\\\\\tt E_p=\dfrac{40\cdot0{,}0016}{2}\\\\\tt E_p=\dfrac{0{,}064}{2}\\\\\boxed{\boxed{\tt E_p=0{,}032\,J}}\end{array}}$