• Matéria: Matemática
  • Autor: petersonpereira
  • Perguntado 9 anos atrás

.preciso de algumas equacoes (raiz de 2)x=4 

3²-x= 1/27
3x-5=27¹-x
5raiz 2x =1/32
100x=+8=1/10 
8x-4=4x+1
9x-2=raiz de 27
91/16)x-²=8x

Respostas

respondido por: 3478elc
1
3²-x= 1/27 ==(3)^-2x = 3^-3 ==> -2x=-3(-1) ==> 2x=3 ==> x = 3/2

3x-5=27¹-x ==> 3^(x-5) = (3^3)^-x ==> x-5= -3x==>x+3x =5 ==> 4x=5==> x = 5/4

5raiz 2x =1/32 ==>(2x)^1/5 = 2^-5==> (2x)^-5= 2^(-5)=>2x = 2 ==> x =1

100x+8=1/10==> 10^2(x+8) = 10^-1 => 2(x+8)= -1=>2x + 16=1=> 2x= - 1 -16
=>X= - 17/2

8x-4=4x+1
2^3(X-4) = 2^2(X+1) ==>3X-12 =2X+2 ==> 3X-2x=2+12 ==> X = 14

9x-2=raiz de 27==> 3^2(X-2) = 3^3/2==> 2X-4 = 3/2 => 4X-8=3==> 4X=8+3 ==> X =11/4

91/16)x-²=8x  sem solucão pq as bases são diferentes.
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