Question

Examine o triângulo retângulo da figura abaixo sendo a medida da hipotenusa iguarda a 8cm

Sen30=1 e cos30=Raiz de 3

2 2

Answer 1

Sabemos que:

$tg(\theta)=\frac{sen(\theta)}{cos(\theta)}$

Logo, substituindo os valores de fornecidos:

$tg(\beta)=\frac{sen(\beta)}{cos(\beta)}\\\\tg(30^\circ)=\frac{sen(30^\circ)}{cos(30^\circ)}\\\\tg(30^\circ)=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}} \\\\tg(30^\circ)=\frac{1}{2}.\frac{2}{\sqrt{3}}\\\\tg(30^\circ)=\frac{1\,.\,2}{2\,.\,\sqrt{3}}\\\\tg(30^\circ)=\frac{1}{\sqrt{3}}\\\\tg(30^\circ)=\frac{1}{\sqrt{3}}.\frac{\sqrt{3}}{\sqrt{3}}\\\\tg(30^\circ)=\frac{1.\sqrt{3}}{\sqrt{3}^2}\\\\tg(30^\circ)=\frac{\sqrt{3}}{3}$

Resp: LETRA A