Question

$x {}^{2} - x + \frac{1}{4 } = 0$
alguém sabe ?

Answer 1

Resposta:

S = {2}

Explicação passo-a-passo:

$x^2-x+\frac{1}{4}=0\\\\MMC=4\\\\4x^2-4x+1=0\\\\\\\Delta=(-4)^2-4(4)(1)\\\Delta=16-16\\\Delta=0\\\\Raizes~reais~e~iguais\\\\x=\frac{4~\pm~0}{2}\\\boxed{x'=x''=2}$