Question

me ajudem pfv nessa equação do 1° garu { 3x+2y=6 { -x+6y=9

Answer 1

Resposta:

x = 9/10 e y = 33/20

Explicação passo-a-passo:

$\left \{ {{3x+2y=6} \atop {-x+6y=9}} \right.\\ \\2y = 6-3x\\y = \frac{6-3x}{2}\\ \\-x + 6.(\frac{6-3x}{2}) = 9\\ -x + \frac{36-18x}{2} = 9\\ -x + 18 -9x = 9\\-10x = 9-18\\x = -9/-10\\x = 9/10\\\\2y = 6-3.(\frac{9}{10})\\2y = 6 -\frac{27}{10}\\2y = \frac{60-27}{10}\\2y = \frac{33}{10}\\ y = \frac{33}{10}.\frac{1}{2} \\y = \frac{33}{20}$