Question

log2(x-3) - log2(x+9) = 3

Answer 1

Resposta:

Explicação passo-a-passo:

$Log_{2}(x-3) - Log_{2}(x+9) = 3\\Log_{2}(x-3) - Log_{2}(x+9) = Log_{2}8\\Log_{2}(x-3/x+9) = Log_{2}8\\\\x-3/x+9 = 8\\x-3 = 8.(x+9)\\x-3 = 8x + 72\\-7x = 75\\x = -75/7$

x ∈ ∅