Question

X2-7x+10=0
X2-5x-6=0

Answer 1

1) x²-7x+10
$b {}^{2} - 4ac$

∆= (-7)²-4.1.10
∆= 49+40
∆= 9
$x = \frac{ - b + - \sqrt{deta} }{2a}$

x= 7±3/2
x'= 10/2 = 5
x"= 4/2 = 2
2) x²-5x-6=0
∆= (-5)²-4.1.-6
∆= 25-24
∆= 1
x= 5±1/2
x'= 6/2= 3
x"= 4/2 = 2
espero ter ajudado