Question

Caucule:

$y = - \frac{1}{2x \sqrt{x} }$

Answer 1

$y = \frac{-1}{2x \sqrt{x} }$



$y = \frac{-1}{2x \sqrt{x} } * \frac{ \sqrt{x} }{ \sqrt{x} }$



$y = -\frac{ \sqrt{x} }{2x*x}$


$y = - \frac{ \sqrt{x} }{2 x^{2} }$


$y = - \frac{ x^{ \frac{1}{2} } }{2 x^{2} }$


$y = - 2 x^{ \frac{-3}{2} }$


$y = - \frac{1x}{2} ^{ \frac{3}{2} }$


$y = - \sqrt{1x ^{3} } / \sqrt{2 ^{3} }$

$y = - \sqrt{ 1x^{3} } / 2 \sqrt{2}$


$y = - \sqrt{2x^{4}} / 4$