Question

sendo x =-b+√b²-4ac , determine o valor de x para a=3,b=-7

Answer 1

x = -b + raiz b² - 4ac
x = 7 + raiz 49 - 4(3)(2)
x = 7 + raiz 49 - 24
x = 7 + raiz 25
x = 7 + 5
x = 12

BONS ESTUDOS!

Answer 2

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\ ,\ \ \ a=3\ ,\ \ \ b=-7$


$x=\dfrac{-(-7)\pm\sqrt{(-7)^2-4(3)c}}{2(3)}$


$x=\dfrac{7\pm\sqrt{49-12c}}{6}$


Daí dependende de c.