Question

por favor me ajudem.....

Answer 1

-x²+6x -5=0 ===> *(-1)

x² -6x +5 = 0
∆=b²-4ac= (-6)²-4.1.5=36-20=16 =>√∆=4
x = -b±√∆/2a
x = 6±4/2
x' = 6+4/2 = 10/2 = 5 ✓
x" = 6-4/2 = 2/2 = 1 ✓

Answer 2

${x}^{2} - 6x + 5 = 0$
${x}^{2} - x - 5x + 5 = 0$
$x \times (x - 1) - 5(x - 1) = 0$