Question

me ajudem pfvr!
x + 3y = 11
5y - 68= 3(x - 1)

Answer 1

x+3y=11
x=11-3y

5y-68=3 (x-1)
5y-68=3x-3
5y=3x-3+68
5y=3x+65
y=3
x+13
5

Mil desculpas se estiver errado .

Answer 2

5y - 68= 3(x - 1)

5y - 68 = 3x - 3

5y - 3x = - 3 + 68

5y - 3x = 65

y = (65 + 3x)/5

x + 3y = 11

x + 3(65 + 3x)/5 = 11        

x + (195 + 9x)/5 = 11            mmc=5

5x + 195 + 9x = 55

5x + 9x = 55 - 195

14x = - 140

x = - 140 / 14

x = - 10

x = - 140 / 8

x = -10

y = (65 + 3x)/5

y = ( 65 + 3*(-10)/5

y = ( 65 - 30) /5

y = 35/5

y = 7

S = {- 10 ; 7 }