Question

Qual a solução do sistema { 3x-4y+3z=1. 2x-y-z=-5. X-3y-z=-6.

Answer 1

3x-4y+3z=1
2x-y-z=-5
X-3y-z=-6


x-3y-z=-6.(-3)
_____________

=> -3x+9y+3z=18



x-3y-z=-6.(-2)
____________

=> -2x+6y+2z=12


3x-4y+3z=1
+ -3x+9y+3z=18
______________
5y+6z=19




2x-y-z=-5
+ -2x+6y+2z=12
______________

5y+z=7



5y+z=7.(1)
5y+6z=19 .(-1)


5z+z=7
-5z-6z=-19
__________

-6z+z=-19+7

-5z=-12

z=-12/-5

z=12/5
__________




5y+z=7

5y=7-z

5y=7-12/5

5y=35-12/5

5y=23/5

25y=23
________

y=23/25
________


X-3y-z=-6

x=-6+3y+z

x=-6+3.(23/25)+12/5

x=-6+69/25+12/25

x=-6+(69+12)/25

x=-6+(81/25)

x=-150+81/25

x=-69/25


s=[(-69/25 ; 23/25 ; 12/25)]


espero ter ajudado!

boa noite!

Answer 2

Resposta:

{3x-4y+3z=1

{2x-y-z=-5

{x-3y-z=-6

------------------

3x-4y+3z=1 x(-2)

2x-y-z=-5 x(3)

--------------------

-6x+8y-6z=-2

6x-3y-3z=-15

---------------------

5y-9z=-17

---------------

2x-y-z=-5

x-3y-z=-6 x(-2)

------------------

2x-y-z=-5

-2x+6y+2z=12

-------------------

5y-9z=-17 x(-1)

5y+z=7

---------------

-5y+9z=17

5y+z=7

-------------

10z=24

z=24/10

z=12/5

5y+12/5=7

25y+12=35

25y=35-12

25y=23

y=23/25

3x-4*23/25+3*12/5=1

3x-92/25+36/5=1

75x-92+180=25

75x+88=25

75x=25-88

75x=-63

x=-63/75

x=-21/25

---------------------

Explicação passo-a-passo: