Question

Quanto e o termo central de (2×+4)8

Answer 1

tc = n+2/2= 8+2/2= 10/2= 5 => p=4

t(p+1) = C(n, p). a^n-p. b^p

t(4+1) = C(8, 4). (2x)^8-4. 4⁴

t(5) = 8.7.6.5/4!. (2x)⁴. 256

t5 = 7.5. 8.6/24. 16x⁴. 256

t5 = 35. 2. 4096x⁴

t5 = 286720x⁴ ✓

Answer 2

Quanto e o termo central de (2x+4)^8

Explicação passo-a-passo:

(2x + 4)^8 = 2^8*(x + 2)^8

2^8 = 256

o termo central é k*x^4

(x + 2)^4

2^4 = 16

C(8,4) = 8!/(8 - 4)!4!

C(8,4) = 8*7*6*5/1*2*3*4 = 70

o termo central = 256*16*70x^4 = 286720x^4