Question

${2}^{x} = \frac{1}{32}$
${7}^{x + 4} = 1$
${4}^{x + 1} = \frac{1}{2}$
${8}^{x} = 16$
${10}^{x} = 0.01$
$( {3}^{x} ) {}^{x + 3} = \frac{1}{9}$

Answer 1

Resposta:

Explicação passo-a-passo:

2^x = 1/32

2^x = 32^-1

2^x= (2^5)^-1

2^x= 2^-5

x= -5

7^x. 7^4 = 1/2

admitindo que y= 7^x

7^4y =1/2

28y= 1/2

y= 1/56

7^x=1/56

7^x= 1^{-56}

7^x= 7^0

x=0