Question

sen (x) =3/5 e x no 1 quadrante ache cos (x) tg (x) cotg(x)

Answer 1

cosx =√1-sen²x =√1 -9/25 =√16/25 = 4/5

tgx=senx/Cosx =3/5 / 4/5=3/5 •5/4= 3/4

cotgx = 1/tgx = 1/ 3/4 = 1• 4/3 = 4/3