Question

log9 (log4 64)+log4 (log3 81)

Answer 1

Acompanhe pela imagem anexa.

Resp: 3/2

Espero ter ajudado!

Answer 2

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{log_9\:(log_4\:64) + log_4\:(log_3\:81) = log_9\:(log_4\:4^3) + log_4\:(log_3\:3^4)}$

$\mathsf{log_9\:(log_4\:64) + log_4\:(log_3\:81) = log_{9}\:3 + log_4\:4}$

$\mathsf{log_9\:(log_4\:64) + log_4\:(log_3\:81) = log_{3^2}\:3 + log_4\:4}$

$\mathsf{log_9\:(log_4\:64) + log_4\:(log_3\:81) = \dfrac{1}{2}\:.\:log_{3}\:3 + log_4\:4}$

$\mathsf{log_9\:(log_4\:64) + log_4\:(log_3\:81) = \dfrac{1}{2} + 1}$

$\boxed{\boxed{\mathsf{log_9\:(log_4\:64) + log_4\:(log_3\:81) = \dfrac{3}{2}}}}$