Question

Ajuda com as resoluções, pfv.

Answer 1

(3 +i)² = 3² +2.3.i +i² = 9+6i-1= 8+6i

(3 -2i)² = 3² -2.3.2i +(2i)²=9-12i -(4)= 5-12i

(2- i)² = 4 -4i +i² = 4 -4i -1 = 3 -4i

(√3 +i)²=3 +2√3i +i²= 3+2√3i -1=2 +2√3 i

Answer 2

olá, vamo la
a)(3+i)^2= 9+6i+i^2
a gnt sabe q i^2= -1
ent fica 9-1+6i = 8+6i
b) 3-2i)^2= 9-12i+4i^2
9-4-12i= 5-12i
c)(2-i)^2= 4-4i-1= 3-4i
d)\/3+i)^2= 3+2\/3i-1
3-1+2\/3i = 2+2\/3i
espero ter ajudado!