• Matéria: Física
  • Autor: gusttt14
  • Perguntado 7 anos atrás

Faça as seguintes conversões (Celsius X Fahrenheit).

a) 15° C
b) 20° F
c) 120° C
d) 38 ° F

Respostas

respondido por: joaovitornunesp4d76l
2

a) Tc = 15° C Tf = 59° F

\frac{Tc}{5} = \frac{Tf-32}{9} \\\frac{15}{5}=\frac{Tf-32}{9}  \\3= \frac{Tf-32}{9} \\27=Tf-32\\-Tf= -32 -27 ^{(-1)}\\Tf= 32+27\\Tf= 59 F


b) Tc ≅ -6,66° C Tf = 20° F

\frac{Tc}{5} = \frac{Tf-32}{9} \\\frac{Tc}{5} = \frac{20-32}{9} \\\frac{Tc}{5} = \frac{-12}{9} \\9Tc=-60\\

Agora passa dividindo: Tc = -60/9 Tc ≅ -6,66


c) Tc = 120° C Tf = 248° F

\frac{Tc}{5} =\frac{Tf-32}{9} \\\frac{120}{5} =\frac{Tf-32}{9} \\ 24 = \frac{Tf-32}{9}\\ 216=Tf-32\\-Tf = -32 -216^{(-1)}\\Tf = 32+216\\Tf = 248


d) Tc ≅ 3,33° C Tf = 28° F

\frac{Tc}{5} =\frac{Tf-32}{9}\\\frac{Tc}{5} =\frac{38-32}{9} \\\frac{Tc}{5}=\frac{6}{9}\\9Tc = 30\\Tc = \frac{30}{9} \\Tc = 3,33


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