Question

2y/3+x-1/6=1-3 (x-2)/4 gente me ajudem

Answer 1

Resposta:

Explicação passo-a-passo:

$\frac{2y}{3}+\frac{x-1}{6}=\frac{1-3(x-2)}{4}\\\\\frac{8y+2(x-1)=3-9(x-2)}{12}\\\\8y+2(x-1)=3-9(x-2)\\8y+2x-2=3-9x+18\\8y=3-9x+18-2x+2\\8y=-11x+23\\\\y=\frac{-11x+23}{8}$