Question

(EPCAr) - Se A= $\frac{ - 5^{3} - {6}^{2} }{ { - 7}^{2} }$ e B= $\frac{( - 5)^{3} + ( -6)^{2} }{( - 7) ^{2} }$ então A - B = $\frac{k}{49}$ onde K=...

a) $250$
b) $72$
c) $- 72$
d) $zero$
e) $178$

Answer 1

Hi.. bom dia! :)

$A = \frac{ - {5}^{3} - {6}^{2} }{ - {7}^{2} } = \frac{ - 125 - 36}{ - 49} = \frac{ 161}{49}$

$B = \frac{( - {5}^{3} ) + ( - {6}^{2}) }{( - {7}^{2}) } = \frac{ - 125 + 36}{49} = - \frac{89}{49}$

$A - B = \\ \\ \frac{161}{49} - ( - \frac{89}{49} ) \\ \\ \frac{161}{49} + \frac{89}{49} \\ \\ \frac{250}{49}$

K vale 250

letra A

Answer 2

Explicação passo-a-passo:

A = (5^3 + 6^2)/49 = (125 + 36)/49 = 161/49

B = (-125 + 36)/49 = -89/49

A - B = (161 + 89)/49 = 250/49

k = 250 (A)