Question

Adotando log de 11 na base 6 = 1,34 e log de 2 na base 6 = 0,39, calcule: c) log de 5,5 na base 6, d)log de 11 na base 2

Answer 1

c)
$log_{6}5.5 = \frac{ log_{6}5.5 }{ log_{6}6 } = \frac{ log_{6}( \frac{11}{2} ) }{1} = log_{6}11 - log_{6}2$
adotando

$log_{6}11 = 1.34 \\ log_{6}2 = 0.39$

$log_{6}11 - log_{6}2 = 1.34 - 0.39 = 0.95$

resposta eh 0,95

d)

$log_{2}11 = \frac{ log_{6}11 }{ log_{6}2 } = \frac{1.34}{0.39}$

a resposta pode ser 1,34/0,39 ou 3,4358974358...