Question

Sendo log 2=0,30 e log 3=0,47 , calcule log 180

Answer 1

 log180 
log(2.9.10) 
log2+log9+log10 
log2+log3²+log10 
log2+2.log3+[log10] 
0,301+2(0,477) +[1] 
0,301+0,954+1 
2,255

Answer 2

Sendo log 2=0,30 e log 3=0,47 , calcule log 180
log (2.3^2.10) = log2 + log3^2 + log 10 ==> log2 + 2log3 + log 10

0,30 + 2(0,47) + 1

1,30 + 0,94

2,24