Question

calcule pela fórmula de baskara
$x ^{2} - 8x + 16 = 0$

Answer 1

x² - 8x + 16= 0

A= 1
B= - 8
C= 16

∆= b² - 4ac

∆= (-8) ² - 4 • 1 • 16
∆= 64 - 64
∆= 0

x= -b ± √∆ /2a (Fórmula de Bhaskara)

x= - (-8) ± √0 / 2 • 1
x= 8 ± 0 /2

x'= 8 + 0 / 2 = 4
x"= 8 - 0 / 2 = 4

S= ( 4)