Question

calcule pela fórmula de baskara
$x ^{2} + 10x + 25 = 0$

Answer 1

x² + 10x + 25 =0 => quadrado perfeito
(x +5)² = 0
(x+5) = 0
x = -5 ✓

por Bhaskara:
∆=10² -4.1.25= 0
x = -b±√∆/2a
x = -10+0/2.1
x' = -10+0/2 = -10/2 = -5✓
x" = -10-0/2 = -10/2 = -5✓
==> S: {-5} ✓