Question

sendo log(625/100)=x, temos que log 5 é:

a)(x+1)/3 b)(x+2)/4 c)(x+1)/5 d)(x+2)/5

Answer 1

 log(625/100)=x 
      x = log 625 - log 100
             
   x = log 25² - log 10²

    x = log (5²)² - log 10² ==> x = log 5^4 - 2log 10

 x = 4log 5 - 2

4log5 = x + 2

log 5 = x + 2
               4

letra B