Question

Simplifique as expressões, obtendo uma única potência.

a)
$\frac{4 {}^{2} \times 8 {}^{3} }{10}$

b)
$\frac{9 {}^{3} \times 27 {}^{2} }{81}$

Answer 1

$a) \: \frac{ {4}^{2} \times {8}^{3} }{10} = \frac{ {2}^{4} \times {2}^{9} }{10} = \frac{ {2}^{4 + 9} }{10} = \\ \\ \frac{ {2}^{13} }{10} = \frac{8192 ^{ \div 2} }{10 ^{ \div 2} } = \frac{4096}{5} = 819.5$

$b) \: \frac{ {9}^{3} \times {27}^{2} }{81} = \frac{ {9}^{3} \times {3}^{6} }{ {9}^{2} } = 9 \times {3}^{6} = \\ {3}^{2} \times {3}^{6} = {3}^{2 + 6} = {3}^{8} = 6561$

Esperoter ajudado!! ^_^