Question

x e a solução de 1 x2-8x+15=0​

Answer 1

∆= b^2 - 4.a.c

∆= (-8)^2 - 4.1.15

∆= 64 - 60

∆= 4

x I,II = -b + - ✓∆ / 2.a

x I,II = -(-8)+ - ✓4 / 2.1

x I,II = 8 + - 2 / 2

x I = 8 + 2 / 2 => 10/2 =>5

x II = 8 - 2 / 2 => 6/2 => 3

X 1 = 5

X 2 = 3