Question

Determine 0,25 mol de molecula de AL(OH)3 Determine o mm e m e calcular a massa em gramas..

Answer 1

MM Al(OH)₃ = 27 + 3 * 16 + 3 * 1

MM Al(OH)₃ = 27 + 48 + 3

MM Al(OH)₃ = 78 g/mol

n = m / MM

0,25 = m / 78

m = 0,25 * 78

m = 19,5 g