Question

como resolver f(1-√ 2)=(1-√ 2)^2-3*1-√2+4?

Answer 1

$f(1 - \sqrt{2} ) = (1 - \sqrt{2} ) ^{2} - 3 \times (1 - \sqrt{2} ) + 4 \\ (1 - \sqrt{2} ) \times (1 - \sqrt{2} ) - 3 + 3 \sqrt{2} + 4 \\ 1 - \sqrt{2} - \sqrt{2} + 2 - 3 + 3 \sqrt{2} + 4 = 0 \\ 1 + 2 - 3 + 4 - \sqrt{2} - \sqrt{2} + 3 \sqrt{2} \\ 4 - 2 \sqrt{2} + 3 \sqrt{2} \\ 4 + \sqrt{2}$