Question

3x elevado a 2 +2x +1 = 0

Answer 1

Resposta:

3x²+2x+1=0

Δ=b²-4ac

Δ=2²-4(3)(1)

Δ=4-12

Δ=-8

$\frac{-b+/-\sqrt{delta} }{2a}$

$\frac{-2+/-\sqrt{-8} }{2(3)}$

$\frac{-2+/-(-8) }{6}$

$\frac{-2+(-8) }{6} = \frac{-2-8}{6}$ = $\frac{-10}{6}$ = $\frac{-5}{3}$

$\frac{-2-(-8) }{6} = \frac{-2+8}{6}$ = $\frac{6}{6}$ = 1