Question

Localize a raiz da equação :()

Answer 1

$\dfrac{5}{9}\cdot x+1=\dfrac{1}{3}\cdot x - 1\\\\\\\dfrac{5}{9}\cdot x-\dfrac{1}{3}\cdot x=-1-1\\\\\\\dfrac{5}{9}\cdot x-\dfrac{1}{3}\cdot x=-2$

O m.m.c entre 3 e 9 é 9. Multiplicando todos os membros da equação por 9:

$9\cdot\dfrac{5}{9}\cdot x-9\cdot\dfrac{1}{3}\cdot x=9\cdot(-2)\\\\\\5x-3x=-18\\\\2x=-28\\\\\\x=\dfrac{-18}{2}\\\\\\\boxed{\boxed{x=-9}}$
__________________

$\dfrac{5}{6}x + 2 = \dfrac{1}{3}x+1\\\\\\\dfrac{5}{6}x-\dfrac{1}{3}x=1-2\\\\\\\dfrac{5}{6}x-\dfrac{1}{3}x=-1$

O m.m.c entre 6 e 3 é 6
Multiplicando todos os membros por 6:

$6\cdot\dfrac{5}{6}x-6\cdot\dfrac{1}{3}x=6\cdot(-1)\\\\\\5x-2x=-6\\\\3x=-6\\\\\\x=\dfrac{-6}{3}\\\\\\\boxed{\boxed{x=-2}}$