Question

alguém para me ajudar pfvr? ​

Answer 1

A)

$\sqrt{900} = 30$

B)

$\sqrt{0.64} = 0.8$

C)

$\sqrt{ \frac{144}{49} } = \frac{12}{7}$

D)

$\sqrt{ \frac{81}{25} } = \frac{9}{5}$

E) ?

F) ??

G)

$\frac{ \frac{2}{2} + 3\sqrt{3} }{ \sqrt{3} } = \frac{1 + 3 \sqrt{3} }{ \sqrt{3} } \\ \frac{4 \sqrt{3} \times \sqrt{3} }{ \sqrt{3} \times \sqrt{3} } = \frac{4 \sqrt{9} }{ \sqrt{9} } = \frac{4 \times 3}{3} = \\ \frac{12}{3} = 4$