Question

Quais as raizes da equação x-3/x²-4 + 1 = 1/x-2

Answer 1

 $\frac{x-3}{ x^{2} -4}+1 = \frac{1}{x-2} \\ \\ \frac{x-3}{(x+2)(x-2)}+1 = \frac{1}{x-2} \\ \\ \frac{(x-3) +(x+2)(x-2)}{(x+2)(x-2)}= \frac{1}{x-2} \\ \\ \frac{(x-3) +(x+2)(x-2)}{(x+2)}= \frac{(x-2)}{x-2} \\ \\ \frac{(x-3) +(x+2)(x-2)}{(x+2)}= 1 \\ \\ (x-3) +(x+2)(x-2)= (x+2) \\ \\ x-3 + ( x^{2} -4) = x+2 \\ \\ ( x^{2} -4) = x+2 - x+3 \\ \\ x^{2} -4 = 5 \\ \\ x^{2} =5+4 \\ \\ x^{2} =9 \\ \\ x=+- \sqrt{9}$ 
Resposta:
x'=-3
x''=3

Answer 2

vc pode me ajuda 1=x^/4