Question

calcule
a) 3^0-3^-1+3^2
b) 2+2^-1+2^-2
c) (-6)^2-4.(-3).(-3)
d) (-7)^2-4.2.(-2)

​

Answer 1

Resposta:

a) 3^0-3^-1+3^2

3^0= 1 -3^-1= 3 3^2= 9

1+3+9= 13

b) 2+2^-1+2^-2

2^-1= 1/2 2^-2= 1/4

2+1/2+1/4= 2.75

c) (-6)^2-4.(-3).(-3)

(-6)^2= 36

36-4.(-3).(-3)=

(-3).(-3)= 9

36-4.9=

36-36= 0

d) (-7)^2-4.2.(-2)

(-7)^2= 49

2.(-2)= -4

49-4.(-4)

-4.(-4)= 16

49-16= 33