Question

São dadas as matrizes A= e b =

$A=\left[\begin{array}{ccc}2&-1&\\0&1&\\&&\end{array}\right] B= \left[\begin{array}{ccc}1&-2&\\-1&0&\\&&\end{array}\right] A matriz x=a^{t} + 2b, onde A^{t}$


A matriz transposta de a, é igual a

Answer 1

Resposta:

Explicação passo-a-passo:

$A=\left[\begin{array}{cc}2&-1\\0&1\end{array}\right]$

Matriz transposta : quem é coluna vira linha e quem é linha vira coluna

$A^{t} =\left[\begin{array}{cc}2&0\\-1&1\end{array}\right]$

$B=\left[\begin{array}{cc}1&-2\\-1&0\end{array}\right]\\\\2B=\left[\begin{array}{cc}1.2&-2.2\\-1.2&0.2\end{array}\right]\\\\2B=\left[\begin{array}{cc}2&-4\\-2&0\end{array}\right]$

$A^{t}+2B= 2B=\left[\begin{array}{cc}2&0\\-1&1\end{array}\right]+\left[\begin{array}{cc}2&-4\\-2&0\end{array}\right]=\left[\begin{array}{cc}2+2&0-4\\-1-2&1+0\end{array}\right]=\left[\begin{array}{cc}4&-4\\-3&1\end{array}\right]$