• Matéria: Matemática
  • Autor: ALVES11111111111
  • Perguntado 7 anos atrás

extrair as raízes por decomposição;

A)
B)
C)
D)
E)
F)
G)
H)
I)​

Anexos:

Respostas

respondido por: VaiAgarrarFera
0

A)

4 \sqrt{108}  =  \\ 108 | 2 \\ 54 |2 \\ 27 |  3 \\ 9 | 3 \\ 3 | 3 \\ 1......... \\  \sqrt{ {2}^{2} \times  {3}^{2}  \times 3 }  = 2 \times 3 \sqrt{3}  = 6 \sqrt{3}  \\  \\ 4 \times 6 \sqrt{3}  = 24 \sqrt{3}

B)

 \sqrt[3]{216}  =  \\ 216 | 2 \\ 108 | 2 \\ 54 | 2 \\ 27 |3 \\ 9 | 3 \\ 3 | 3 \\ 1 | .......... \\  \sqrt{ {2}^{2}  \times 2 \times  {3}^{2} \times 3 }  = 2 \times 3 \sqrt{2 \times 3}  \\  \\ 6 \sqrt{6}

C)

2 \sqrt[2]{54}  \\ 54 | 2 \\ 27 | 3 \\ 9 | 3 \\ 3 | 3 \\ 1 | ............ \\  \sqrt{2 \times  {3}^{2} \times 3 }  = 3 \sqrt{2 \times 3}  = 3 \sqrt{6}  \\  \\ 2 \times 3 \sqrt{6}  = 6 \sqrt{6}

D)

 \sqrt{96}  =  \\  \\ 96 | 2 \\ 48 |2 \\ 24 |  2 \\ 12 | 2 \\ 6 | 2 \\ 3 | 3 \\ 1 | .......... \\  \sqrt{ {2}^{2}  \times  {2}^{2}  \times 2 \times 3}  = 2 \times 2 \sqrt{6}  = 4 \sqrt{6}

E)

 \sqrt{60}  =  \\60 | 2 \\ 30 | 2 \\ 15 | 3 \\ 5 | 5 \\ 1 | ............ \\   \sqrt{ {2}^{2}  \times 3 \times 5}  = 2 \sqrt{15}

F)

 - 5 \sqrt{48}  =  \\  \\ 48 | 2 \\ 24 | 2 \\ 12 | 2 \\ 6 | 2 \\ 3 | 3 \\ 1 | ........ \\  \sqrt{ {2}^{2}  \times  {2}^{2} \times 3 }  = 2 \times 2 \sqrt{3}  = 4 \sqrt{3}  \\  \\  - 5 + 4 \sqrt{3}  =  -  \sqrt{3}

G)

 \sqrt{192}  \\  \\ 192 | 2 \\ 96 | 2 \\ 48 | 2 \\ 24| 2 \\ 12 | 2 \\ 6 | 2 \\ 3 | 3 \\ 1 | ............. \\  \sqrt{ {2}^{2} \times   {2}^{2}  \times  {2}^{2}  \times 3  }  =  \\  \\ 2 \times 2 \times 2 \sqrt{3}  = 8 \sqrt{3}

H)

2 \sqrt{243}  =  \\ 243 | 3 \\ 81 | 3 \\ 27 | 3 \\ 9 | 3 \\ 3 | 3 \\ 1 | .......... \\  \sqrt{ {3}^{2}  \times  {3}^{2} \times 3 }  = 3 \times 3 \sqrt{3}  = 9 \sqrt{3}  \\  \\ 2 \times 9 \sqrt{3}  = 18 \sqrt{3}

I)

 \sqrt[3]{80}  =  \\ 80 | 2 \\ 40 | 2 \\ 20 | 2 \\ 10 | 2 \\ 5 | 5 \\ 1 | .....  \\ \sqrt{ {2}^{3}  \times 2 \times 5}  = 2 \sqrt[3]{2 \times 5}  = 2 \sqrt[3]{10}  \\

J)

 - 3 \sqrt{121}  =  \\  121 | 11 \\ 11 | 11 \\ 1 | .......... \\  {11}^{2}  \\  \\  \sqrt{ {11}^{2} }  = 11 \\   \\ - 3 + 11 = 8

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