Question

Alguém me socorre, por favor

Answer 1

ln10=2,3

ln (a³)-log (a) +2 ln(a)/log (a)

$ln(x) = log_{e}(x)$

$log_{b}( {a}^{n} ) = n \times log_{b}(a)$

3 ln(a) -log(a) +2 ln(a)/log(a)

5 ln(a) -log(a)/log(a)

5log(e)(a) -log(a)/log(a)=m

5log(e)(a)-log(a)=mlog(a)

5log(e)(a)=mlog(a)+log(a)

5log(e)(a)=(m+1)(log(a))

m+1=5log(e)(a)/log(a)

m+1=5.log(e)

m+1=5.1/ln10

m+1=5/2,3

m=5/2,3 -1

m≈1,17

$\boxed{ \boxed{ \mathsf{ alternativa\: \huge{(e).}}}}$