Question

Observe a representação de três partículas, A, B e C, fixas no vácuo...​

Answer 1

Resposta:

A = 172,8N

B = 120N

C = 32,8N

Explicação da Resposta:

       Fac<---A----->Fab<-----B-------->Fbc<---------C--->Fac

         

a) Fa = Fab - Fac = 180N - 7,2N = 172,8N

$Fab = \frac{9.10^{9} .2.10^{-6}.4.10^{-6}}{(2.10^{-2}) ^{2}} =\frac{9.10^{9}.2.10^{-6}.4.10^{-6}}{4.10^{-4}} = 9.10^{9}.2.10^{-6}.10^{-2}=180N$

$Fac = \frac{9.10^{9}.2.10^{-6}.10^{-6}}{(5.10^{-2})^{2}}= \frac{9.10^{9}.2.10^{-6}.10^{-6}}{25.10^{-4}} = \frac{180}{25} = 7,2N$

b)Fb = Fab - Fbc = 180N - 40N = 120N

$Fbc = \frac{9.10^{9}.4.10^{-6}.10^{-6}}{(3.10^{-2})^{2}}= \frac{9.10^{9}.4.10^{-6}.10^{-6}}{9.10^{-4}}=10^{13}.4.10^{-6}.10^{-6}=40N$

c)Fc = Fbc - Fac = 40N - 7,2N = 32,8N

Answer 2

Resposta:

a)180-7,2=172,8 N

b)180-40=140 N

c)40-7,2=32,8 N

Explicação:

a) Fab=9*1092 * 10-6 * 4 * 10-6(2 * 10-2)2=72 * 10-34 * 10-4=72 * 104=7204=180 N

Fac=9*1092 * 10-6 * 1 * 10-6(5 * 10-2)2=18 * 10-325 * 10-4=18 * 1025=18025=7,2 N

180-7,2=172,8 N

b)Fba=9*1092 * 10-6 * 4 * 10-6(2 * 10-2)2=72 * 10-34 * 10-4=72 * 104=7204=180 N

Fbc=9*1094 * 10-6 * 1 * 10-6(3 * 10-2)2=36 * 10-39 * 10-4=36 * 109=3609=40 N

180-40=140 N

c)Fcb=9*1094 * 10-6 * 1 * 10-6(3 * 10-2)2=36 * 10-39 * 10-4=36 * 109=3609=40 N

Fca=9*1092 * 10-6 * 1 * 10-6(5 * 10-2)2=18 * 10-325 * 10-4=18 * 1025=18025=7,2 N

40-7,2=32,8 N