• Matéria: Matemática
  • Autor: esterkaren91
  • Perguntado 7 anos atrás

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Anexos:

Respostas

respondido por: mithie7552
1

Resposta:

a)\\ \sqrt{648} \div\sqrt{6} =  \sqrt{648\div6} =\\ \\ \sqrt{108} =\sqrt{2^2.3^2.3} =2.3\sqrt{3} =6\sqrt{3} \\ \\ b)\\ \sqrt{76} .\sqrt{12} =\sqrt{76.12} =\\ \\ \sqrt{912} =\sqrt{2^2.2^2.3.19} =2.2\sqrt{3.19} =4\sqrt{57} \\ \\ c)\\ \sqrt[3]{1875} \div\sqrt[3]{3} =\sqrt[3]{1875\div3} =\\ \\ \sqrt[3]{625} =\sqrt[5]{5^3.5} =5\sqrt[3]{5}

d)\\ \sqrt[4]{144} \div\sqrt[4]{9} =\sqrt[4]{144\div9} =\sqrt[4]{16} =\sqrt[4]{2^4} =2\\ \\ e)\\ \sqrt{12} .\sqrt{14} \div\sqrt{3} =\sqrt{12.14\div3} =\\ \\ \sqrt{168\div3} =\sqrt{56} =\sqrt{2^2.2.7} =2\sqrt{14} \\ \\ f)\\ \sqrt[3]{320} \div\sqrt[3]{5} .\sqrt[3]{20} =\sqrt[3]{320\div5.20} =\\ \\ \sqrt[3]{64.20} =\sqrt[3]{1280} =\sqrt[3]{2^3.2^3.2^2.5} =4\sqrt[3]{20}

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