Question

Quanto seria o resultado da38?

Answer 1

$x + 1 = \frac{8 - x}{x} \\ x(x + 1) = 8 - x \\ {x}^{2} + x = 8 - x \\ {x}^{2} + x + x - 8 = 0 \\ {x}^{2} + 2x - 8 = 0$

$d = delta$

$d = {b}^{2} - 4ac \\ d = {2}^{2} - 4 \times 1 \times ( - 8) \\ d = 4 + 32 \\ d = 36$

$x = \frac{ - b \frac{ + }{ - } \sqrt{d} }{2a} \\ x = \frac{ - 2 \frac{ + }{ - } \sqrt{36} }{2 \times 1} \\ x = \frac{ - 2 \frac{ + }{ - }6 }{2} \\ \\ {x}^{1} = \frac{ - 2 + 6}{2} = \frac{4}{2} = 2 \\ \\ {x}^{2} = \frac{ - 2 - 6}{2} = \frac{ - 8}{2} = - 4$

${( {x}^{1} )}^{2} + {( {x}^{2} )}^{2} = \\ {2}^{2} + ( { - 4)}^{2} = \\ 4 + 16 = 20$