• Matéria: Matemática
  • Autor: lavaraujo10
  • Perguntado 7 anos atrás

Resolva:

A) (1/9+6/15÷3/5)²
B)(7/8÷1/4+1/2)⁴
C)(3/4.8/3-5/12÷10/3)²

Me ajudem pfvr

Respostas

respondido por: fabioluciojrp8doab
0

Resposta:

Explicação passo-a-passo:

Olá...

a) (\frac{1}{9} + \frac{6}{15} : \frac{3}{5})^{2} =

(\frac{1}{9} + \frac{2}{5} : \frac{3}{5})^{2} =

(\frac{1}{9} + \frac{2}{5} . \frac{5}{3})^{2} =

(\frac{1}{9} + 2 . \frac{1}{3})^{2} =

( \frac{1}{9} + \frac{2}{3})^{2} =

(\frac{1 + 6}{9})^{2} =

(\frac{7}{9})^{2} =

\frac{49}{81}

B) (\frac{7}{8} : \frac{1}{4} + \frac{1}{2})^{4} =

(\frac{7}{8} . \frac{4}{1} + \frac{1}{2})^{4} =

( \frac{7}{2} . 1 + \frac{1}{2})^{4} =

(\frac{7}{2} + \frac{1}{2})^{4} =

(\frac{8}{2})^{4} =

(4)^{4} =

256

C) (\frac{3}{4} . \frac{8}{3} - \frac{5}{12} : \frac{10}{3})^{2} =

( 1 . 2 - \frac{5}{12} . \frac{3}{10})^{2} =

(2 - \frac{1}{4} . \frac{1}{2})^{2} =

(2 - \frac{1}{8})^{2} =

(\frac{16 - 1}{8})^{2} =

(\frac{15}{8})^{2} =

\frac{225}{64}

espero ter ajudado!

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