Question

(0,1)elevado a 3 mais (0,12)elevado a 2 é:

Answer 1

$\left(0,1\right)^3+\left(0,12\right)^2~=~\left(\frac{1}{10}\right)^3+\left(\frac{12}{100}\right)^2~=\\\\\\=~\frac{1^3}{10^3}+\frac{12^2}{100^2}~=~\frac{1}{1000}+\frac{144}{10000}~=\\\\\\=~\frac{10~.~1~+~1~.~144}{10000}~=~\frac{154}{10000}~=~\boxed{0,0154}$