Question

dada a matriz a=/1 -1/ /-1 1 / caucule 2.a+8.a​

Answer 1

Resposta:

Explicação passo-a-passo:

$a=\left( \begin{array}{cc}1 & -1 \\ -1 & 1\end{array} \right)$

$2.a=\left( \begin{array}{cc}2 & -2 \\ -2 & 2\end{array} \right)$

$8.a=\left( \begin{array}{cc}8 & -8 \\ -8 & 8\end{array} \right)$

2.a+8.a​

$\left( \begin{array}{cc}2 & -2 \\ -2 & 2\end{array} \right) +\left( \begin{array}{cc}8 & -8 \\ -8 &8\end{array} \right)=\left( \begin{array}{cc}10 & -10 \\ -10 & 10\end{array} \right)$