Question

Sendo cos x= 3/5, com 0<x<π/2, calcule o valor de:

a) sen x
b) tg x
c) cos 2x
d) sen 2x
e) tg 2x​

Answer 1

Explicação passo-a-passo:

Sendo cos(x) = 3/5, com 0<x<π/2, calcule o valor de:

cos^2(x) + sen^2(x) = 1

9/25 + sen^2(x) = 25/25

sen^2(x) = 16/25

a) sen(x ) = 4/5

b) tg(x ) = 4/3

c) cos(2x ) = cos^2(x) - sen^2(x) = 9/25 - 16/25 = -7/25

d) sen(2x ) = 2sen(x)*cos(x) = 2*4/5*3/5 = 24/25

e) tg(2x​) = -24/7