Question

resolva com a fórmula de Bhaskara: x^2+6x+1=0​

Answer 1

∆=(6)² -4.1.1=32 => √∆=√32=√16.2 =4√2

x = -6±4√2/2

x = 2(-3±2√2)/2

x' = (-3+2√2) ✓

x" = (-3-2√2) ✓