• Matéria: Matemática
  • Autor: lopesjulia9151
  • Perguntado 7 anos atrás

qual o vertice de f (x)= x2+2x-4

Respostas

respondido por: jbsenajr
1

Resposta:

Explicação passo-a-passo:

a=1\\b=2\\c=-4\\\\\\Xv=\dfrac{-b}{2a}=\dfrac{-2}{2.1}=-1\\\\\\Yv=\dfrac{-\Delta}{4a}=\dfrac{-(2^{2}-4.1.(-4))}{4.1}=\dfrac{-(4+16)}{4}=\dfrac{-20}{4}=-5\\\\\\\\(Xv,Yv)=(-1,-5)

respondido por: joasUZUMAKI
0
xv = -b/2.a

xv = -2/2.1

xv = -1

y = x2+2x-4

y = (-1)^2+2(-1)-4

y = 1 - 2 - 4

y = -5

Xv = -1
Yv = -5
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