Question

Determine a massa 100 mols de c 12 h 22 o 11

Answer 1

m (C₁₂H₂₂OH) = ?

n (C₁₂H₂₂O₁₁) = 100mol

M (C₁₂H₂₂O₁₁) = 12×12,01 + 22×1,01 + 11×16 = 342,34 g/mol

M = m/n ⇔ m = n×M ⇔

             ⇔ m = 100×342,34 ⇔

             ⇔ m = 34.234 g ⇔

             ⇔ m = 34,234 kg